I know But I can't understand what there is * before (uint16_t*) BSP said that this is dereference pointer With searching "dereference pointer" in Google, I can reach to an...
Hi What's this: *(uint16_t*) Really I can't understand (uint16_t*) means that it's an pointer casting But when there is * before pointer casting, what's happens exactly? ...
I understand now Tnx We can use a variable like uint16_t instead of #define?
For what? When I write : #define Memlocation *(uint16_t*)(0x550000) Memlocation = 33; What happens in the memory?
No I just wanna to see that how must I write this It should look something like this? uint16_t* varname=0x550000