I know But I can't understand what there is * before

Question

I know But I can't understand what there is * before

(uint16_t*)

BSP said that this is dereference pointer

With searching "dereference pointer" in Google, I can reach to answer?

Or please explain this in the group

Tnx

0

20.07.2020

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Пользователь 61654

what is this code for?

0

20.07.2020

Tute Ávalos · Accepted Answer

Tute Ávalos

(uint16_t*) is the cast. You are "transforming" the number 0x550000 in a memory address (pointer)... But to access the content of the that address you need to use *... Change a bit the code, may be it's more compreensive: #define memaddress (uint16_t*)0x550000 // ... *memaddress = 33;

0

20.07.2020

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I know But I can't understand what there is * before

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