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Maybe a stupid question, but you can reduce variance of

rolling dice by rolling multiple dice. Would this reduce block time variance if instead of just one hash we would opt for finding 4 hashes for a block? (with difficulty adjusted of course)

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you're not finding hashes tho, you're finding full blocks that result in a particular block hash, you try to "cheat" this somehow I think you'd end up reinventing reducing blocktime but it would be a somewhat different data structure

bitcoincashautist
you're not finding hashes tho, you're finding full...

But couldn’t you hash the block with multiple algorithms?

Remora_101🟢- Автор вопроса
bitcoincashautist
you're not finding hashes tho, you're finding full...

Yes I have no idea how the he hashes for the block are exactly "rolled" so I don't know if this is even possible.

Dustin 🪐
But couldn’t you hash the block with multiple algo...

doesn't matter, multiple algorithms is still 1 blackbox hash op

bitcoincashautist
doesn't matter, multiple algorithms is still 1 bla...

Not sure what I don’t understad here. If the SHA256 and MD5SUM hash of a block both need to start with 8 zeroes, isn’t that far less likely than one of them starting with 16 zeroes?

Dustin 🪐
Not sure what I don’t understad here. If the SHA2...

what content are you hashing? the same block header? then let's say you make a requirement that both the sha256 and md5 must start with 0 zeroes and you find a block which results in sha256 but not md5 - you have to rehash with both again, not just with md5, because to reroll md5 you have to change the content, and that will change the sha256 too - there's no progress like ok i got 1/2 now just to grind the other one

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