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The paper say the fee is deterministic before truly send

a transaction. And the fee is calculated according tx size, which is so different from ethereum whose gas is additionally determine by the compute consumption of opcodes. Would it be unfair?

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As the transaction is validated in advance and the free is calculated in advance in Cardano it is also not possible to pay for a failed transaction like on some other chains. The transaction either succeeds and fees are paid or neither of these two events happen. E.g. it could happen the UTXO specified is spent by the time the transaction is submitted to the mempool, the transaction would in case of failure not go far but stop at the first relays it reaches

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