$Sql = "insert into crypted (message, encrypted, keys) values('$message', '$encrypted',

Question

$Sql = "insert into crypted (message, encrypted, keys) values('$message', '$encrypted',

'$token')";

pls why my flutter app return this error?

Uncaught mysqli_sql_exception: You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'keys) values('salut serge', 'l11NINHOsßu11NINHOaßt11NINHOlß', '.5b24800526...' at line 1 in C:\xampp\htdocs\crp\crp.php:9

#dart #english #programming

0

01.07.2022

6 ответов

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Serge Автор вопроса

ManBearPig
This comes from your backend (it's look like Lavar...

i fixe the issue tks

0

01.07.2022

ManBearPig

Serge
i fixe the issue tks

One more questions) Where issue was coming from?

0

01.07.2022

Serge Автор вопроса

ManBearPig
One more questions) Where issue was coming from?

Keys is a non_use column Name

0

01.07.2022

ManBearPig

Serge
Keys is a non_use column Name

=) i may propose to you to create stored procedures for each one UC)

0

01.07.2022

ManBearPig

Serge
Keys is a non_use column Name

Luck!=)

0

01.07.2022

ManBearPig · Accepted Answer

ManBearPig

This comes from your backend (it's look like Lavarel/php) I'm not sure, but a thet php language, you should to use PDO, and pass into DML prepared arguments, not to pas directly.!

0

01.07.2022

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$Sql = "insert into crypted (message, encrypted, keys) values('$message', '$encrypted',

6 ответов

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