The definition of Flavor is very simple: interface Flavoring<FlavorT> {

Question

The definition of Flavor is very simple: interface Flavoring<FlavorT> {

_type?: FlavorT;
}
export type Flavor<T, FlavorT> = T & `Flavoring<FlavorT>;

We can then use Flavor to define new ID types:

type PersonId = Flavor<number, “Person”>
type BlogPostId = Flavor<number, “BlogPost”>

Because the _type property of Flavoring is optional, implicit conversion is supported:

const personId : PersonId = 1; // OK
const person: Person = personLikeStructure // OK

but we get the safety of branding in that incompatible types don’t mix:

const blogPostId : BlogPostId = personId; // Error!

#programming #russian #typescript

0

03.09.2020

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artalar · Accepted Answer

artalar

Еще раз, такой тип нельзя использовать как индекс

0

03.09.2020

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The definition of Flavor is very simple: interface Flavoring<FlavorT> {

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