Def parse_page_of_categories(links): for i in links:

Question

Def parse_page_of_categories(links): for i in links:

os.mkdir(i.replace('/', ''))
title = i.replace('/', '')
pagination = 0
status = True
r = requests.get('https://marketsakhcom.ru'+str(i))
with open(f'{i}{pagination}.html', 'w', encoding='utf-8') as f:
f.write(r.text)
while status:
try:
print(pagination )
pagination += 1
r = requests.get('https://marketsakhcom.ru'+str(i)+'?page='+str(pagination))
with open(f'{title}/{pagination}.html', 'w', encoding='utf-8') as f:
f.write(r.text)
except Exception as ex:
print(ex)
status = False

#backend #programming #python #russian

0

08.08.2022

1 ответов

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Mike Tyson · Accepted Answer

Mike Tyson

Это можно очень сильно оптимизировать

0

08.08.2022

170 похожих чатов

Def parse_page_of_categories(links): for i in links:

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