Type NRange<T extends number, U extends any[] = []> =

Question

Type NRange<T extends number, U extends any[] = []> =

U['length'] extends T ? U : NRange<T, [...U, 0]>

type Flatten<T, U extends any[] = []> = T extends []
? U
: T extends [infer F, ...infer R]
? Flatten<R, [...U, ...Flatten<F>]>
: [...U, T]

type TupleSum<T extends number[]> = Flatten<{ [K in keyof T]: NRange<T[K]> }>['length']

type A = TupleSum<[1, 2, 3]>

#programming #russian #typescript

0

14.05.2023

1 ответов

13 просмотров

Dima Сахар · Accepted Answer

Dima Сахар

Это древнегреческий?

0

14.05.2023

169 похожих чатов

Type NRange<T extends number, U extends any[] = []> =

1 ответов

Похожие вопросы