Type NRange<T extends number, U extends any[] = []> =

Question

Type NRange<T extends number, U extends any[] = []> =

U['length'] extends T ? U : NRange<T, [...U, 0]>

type Flatten<T, U extends any[] = []> = T extends []
? U
: T extends [infer F, ...infer R]
? Flatten<R, [...U, ...Flatten<F>]>
: [...U, T]

type TupleSum<T extends number[]> = Flatten<{ [K in keyof T]: NRange<T[K]> }>['length']

type A = TupleSum<[1, 2, 3]>

#programming #russian #typescript

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14.05.2023

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Dima Сахар · Accepted Answer

Dima Сахар

Это древнегреческий?

0

11 месяцев назад

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Type NRange<T extends number, U extends any[] = []> =

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