Const path = require("path"); module.exports = { mode: "development",

Question

Const path = require("path"); module.exports = { mode: "development",

devtool: "inline-source-map",
entry: "./index.ts",
target: "async-node",
context: path.resolve(__dirname, "src"),

output: {
filename: "./bundle.js"
},
resolve: {
// Add .ts and .tsx as a resolvable extension.
extensions: [".ts", ".tsx", ".js"]
},
module: {
rules: [
// all files with a .ts or .tsx extension will be handled by ts-loader
{ test: /\.tsx?$/, loader: "ts-loader", options: { transpileOnly: true } }
]
}
};

#backend #javascript #node.js #programming #russian

0

15.06.2018

1 ответов

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Anatoliy Khomyakov · Accepted Answer

Anatoliy Khomyakov

Спасибо. Попробую.

0

15.06.2018

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Const path = require("path"); module.exports = { mode: "development",

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