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I hate Maths because it's confusing sometimes n⁰ =1 0ⁿ = 0 but

what is 0⁰?

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L hospital 😅😆

0^0 is undefined in most mathematics.

It's undefined, but the agreed value is 1, until proven otherwise

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Wolfram has different view of the world of that ma...

Wolfram alpha limits are calculated using algorithms. 0^0 is indeterminate. The value depends on what f(x)^g(x); f(x) -> 0 and g(x) -> 0 you take. As for the function x^x in question, lim x^x i can make this a inf/inf form by transforming it into e^lim(lnx/1/x) Using l hospital rule e^lim(1/x/-1/x^2) e^lim(-x) e^0 1

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Manav | avoid unnecessary messaging me
Wolfram alpha limits are calculated using algorith...

was checking on the graph actually. Wolfram has better precision than most languages

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Manav | avoid unnecessary messaging me
It is still an approximation

true. but atleast it beats my calculator on the nearest to zero it can reach

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true. but atleast it beats my calculator on the ne...

Lol, calculators can do some weird shit as well haha. I remember a video, lemme find it

n^(0) = n^(1-1) = n^(1) * n^(-1) = n * (1/n) = 1 if n != 0 then n^0 = 1 But when n = 0, (1/n) is undefined so we calculate its limit to find out what it could be lim n * (1/n); n -> 0; = 1 Because when its approaching 0 and its not equal to 0 it behaves like other numbers we cancel n out and get 1 as a result

Nader Jafari
n^(0) = n^(1-1) = n^(1) * n^(-1) = n * (1/n) = 1 i...

This is not correct, taking a function which is of the form 0^0 and then taking it's limit is not the way to determine the value 0^0 approaches to Take this expression for instance, (e^(-1/x))^x this approaches 0^0 as x = 0 As x->0 lim(e^(-1/x)) = 0 As x->0 lim(x) = 0 But lim(e^(-1/x))^x = 1/e as x -> 0 And not just this, there are thousands of ways you can approach 0^0 and end up with a value different than 1 0^0 is an indeterminate form. By definition it is a form which can't be evaluated by replacing sub expressions by their limits The reason 0^0 is agreed to have the value of 1 because a lot of the theorems hold true for this value. There isn't a formal proof yet to this and trying to prove it using limits is not correct

Manav | avoid unnecessary messaging me
This is not correct, taking a function which is of...

x^n can be interpreted as multiplying 'x' to itself for 'n' times (or, is that wrong?). As per this, 0^0 should be 0 only, right?

Manav | avoid unnecessary messaging me
This is not correct, taking a function which is of...

Yes but when someone hates math you dont explain to them using e and limits involving powers

Nader Jafari
Yes but when someone hates math you dont explain t...

I guess :) but still that can cause misunderstanding in the longer run

Velan Chandrasekar
x^n can be interpreted as multiplying 'x' to itsel...

No, x^0 is a weird thing. It is an extension of the definiton x^n = x * x * x... n times * x Where x and n are whole numbers

0^0 is an indeterminate form

drunktimelord
that's not how limits work

I was not even talking about limits, it is an agreed value, read this: https://t.me/c/1142198149/502174

Manav | avoid unnecessary messaging me
I was not even talking about limits, it is an agre...

i don't think there's a point to having an "agreed upon value" for an indeterminate form

drunktimelord
i don't think there's a point to having an "agreed...

It has value, for instance binomial expansion of (1 + x)^n makes sense for x= 0 and n= 0 That value is also used in computer science so you woudn't have to write a special case for 0^0

Manav | avoid unnecessary messaging me
Yep.

it's probably because the limit is 1 in that case :/ and not because the limit is usually 1

drunktimelord
it's probably because the limit is 1 in that case ...

That's not how limit works as you said youtself. Limit of an indeterminate form heavily depends on the way you approach it.

Manav | avoid unnecessary messaging me
This is not correct, taking a function which is of...

huh i thought any equation with x→0 had a fixed limit (1/e in this case)

Manav | avoid unnecessary messaging me
I don't understand what you're asking about here.

you're saying limit depends on approach, I'm saying limit is fixed

drunktimelord
you're saying limit depends on approach, I'm sayin...

For an indeterminate form its not. Take x/sinx as x->0 And Take x^2/sinx as x->0 Both are 0/0 indeterminate forms, Both will have 0/0 at x = 0 But their limit is different lim(x/sinx)= 1 lim(x^2/sinx) = 0

Manav | avoid unnecessary messaging me
For an indeterminate form its not. Take x/sinx as...

I'm not saying 0/0 is always 1 (that's what you're saying, for 0^0 to be agreed to be 1) I'm saying eg. sin(x)/x for x->0 is always 1, that's correct at least, right?

drunktimelord
I'm not saying 0/0 is always 1 (that's what you're...

I was just saying that some mathematicians agree that 0^0 is 1, it is not the actual value as it is undefined Yes lim(sinx/x) as x-> 0 is always 1

Manav | avoid unnecessary messaging me
I was just saying that some mathematicians agree t...

those mathematicians should be told that newton didn't die to hear this shit

drunktimelord
those mathematicians should be told that newton di...

There are research papers about it. And for discrete mathematics it can make sense as a lot of algebraic expressions tend to give that value.

Manav | avoid unnecessary messaging me
There are research papers about it. And for discre...

yeah well, not explaining in a paper why you took a 0^0 indeterminate's value to be 1 is alright, can't explain everything in a paper but at least it is provable in those cases right? instead of just assuming it

drunktimelord
those mathematicians should be told that newton di...

Newton was against Cartesian geometry and he was an alchemist dedicated to find secret messages from God in the Bible

drunktimelord
Einstein smoked weed

Yes, but what I meant is that Newton was kind of a bullshit factory

drunktimelord
yeah well, not explaining in a paper why you took ...

I guess 🤔, they must have done some empirical proof or something.

DᴜᴍʙMᴀʜʀᴇᴇᴏ
Yet he found it inelegant

Oh okay, i've read his work pushed forward eculidian geometry replacing perspective geometry which used to be an important subject

DᴜᴍʙMᴀʜʀᴇᴇᴏ
Then what I read is false, thanks for the info

Here, you might find this interesting: https://youtu.be/NYK0GBQVngs

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