start a web-server
- you specify actions and requests and it will follow it ?
NO CODE !
For example in a configuration file, you have :
GET /name
param
echo 'request from %paran%'
POST /fullname
param1, param2
mkdir param1 param2
The first line is the request
The second parameters
The third is the command line it will execute 🤔
Then run : command --port 30 --conf myconfig.txt
Probably doesn't exist since literally giving out remote code execution isn't the greatest idea lol
mhh... am facing a situation where i need that lol !
Everybody is free of commiting suicide. you can run a php server, and then https://www.php.net/manual/en/function.exec.php run as root, so the attacker have it easier!
https://github.com/Sanix-Darker/dycow i made something... and it works pretty fine following my requirements.
To run remote commands it’s standard to use SSH There’s also apps for your phone. For strong security, use ssh keys 🔑
i was not searching to run remote ssh commands but able to create a quick rest api service that can receive some parameters, do a specific stuff and respond 🤔
Oh I see. A quick laravel app with background jobs would do the trick. Autentification included. There’s docker images ready to deploy. The hole process is 20min
yo about docker
interesting thanks ! The thing is i was making this tool for my raspberry pi where i wanted to start a tiny web-server, for laravel it was too much to install, same for docker that is realy huge... With dycow you have only 3 steps : - Create a configuration file for example : - GET /test?name cmd: echo 'Custom command !!!' res: Hello #name# ! And in the CLI, hit : pip install dycow dw 3000 conf_file It will run on port 3000 and following rules in the conf_file
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