Hi guys, i am rewriting my old code and did

Question

Hi guys, i am rewriting my old code and did

a refactoring like this:
https://www.toptal.com/developers/hastebin/igutaripac.py

however, it got me thinking: is there a way to make the variable = variant1 or variant2 or variant3 or ... expression more concise?
i suppose i can write my own function like this:
def multiple_or(*args):
if len(args) == 1:
return args[0]
return multiple_or(*(args[:-1])) or args[-1]

but, is there a built-in function that does that?

0

25.12.2021

10 ответов

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artemetra 🇺🇦 [less active] Автор вопроса

drunktimelord
any(...)

any returns a bool though, i need the item

0

25.12.2021

drunktimelord

artemetra 🇺🇦 [less active]
any returns a bool though, i need the item

you don't need it to be recursive then, though

0

25.12.2021

harꭑony5 🐦‍🔥 ↺

You can also use itertools: from itertools import dropwhile from operator import not_ def multiple_or(seq, default=None): return next(dropwhile(not_, seq), default) You can also check out the "first_true" definition here: https://docs.python.org/3/library/itertools.html?highlight=iter#itertools-recipes

0

25.12.2021

artemetra 🇺🇦 [less active] Автор вопроса

harꭑony5 🐦‍🔥 ↺
You can also use itertools: from itertools import...

first_true is what i was looking for!! thanks :D

0

25.12.2021

Fan / Ac

harꭑony5 🐦‍🔥 ↺
You can also use itertools: from itertools import...

why import operator.not from operator import not and import operator operator.not is throwing syntax error

0

25.12.2021