I have a class: class Stuff(BaseModel): value: float

Question

I have a class: class Stuff(BaseModel): value: float

date: datetime

How can I remove from a list[Stuff] all objects that have timedelta between them less than, say, 10 minutes?

I don’t need the exact code, just the algorithm in plain English would suffice. Thanks!

0

15.05.2022

7 ответов

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Usma Csce Автор вопроса

artemetra 🇺🇦 [less active]
hint: >>>a = [1,2,3,4] >>>list(zip(a, a[1:])) [(1...

ooooh, thanks!

0

15.05.2022

Usma Csce Автор вопроса

artemetra 🇺🇦 [less active]
hint: >>>a = [1,2,3,4] >>>list(zip(a, a[1:])) [(1...

Nope, still can’t figure it out( I’m trying things like for x, y in c: if abs(x.date - y.date) > timedelta(minutes=5): lst.append(x) lst.append(y)

0

15.05.2022

// AlenPaulVarghese //

Usma Csce
Nope, still can’t figure it out( I’m trying thing...

what is c here?

0

15.05.2022

Usma Csce Автор вопроса

// AlenPaulVarghese //
what is c here?

zip

0

15.05.2022

// AlenPaulVarghese //

Usma Csce
zip

zip on ?

0

15.05.2022

$harꭑony5 ¯\_㋡_/¯-↺$ harꭑony5 ¯\_㋡_/¯ ↺

Usma Csce
Nope, still can’t figure it out( I’m trying thing...

Maybe itertools.pairwise might help

0

15.05.2022

artemetra 🇺🇦 [less active] · Accepted Answer

artemetra 🇺🇦 [less active]

hint: >>>a = [1,2,3,4] >>>list(zip(a, a[1:])) [(1, 2), (2, 3), (3, 4)]

0

15.05.2022

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