Def integer(x): count = 0 for item in x: if item.isdigit(): count +=1 if count

Question

Def integer(x): count = 0 for item in x: if item.isdigit(): count +=1 if count

>=1:
return True
return False

def checked_str(x):
count_lower = 0
count_upper =0
for item in x:
if item.isalpha():
checked = item is item.upper()
if checked :
count_upper +=1
else:
count_lower +=1

if (count_lower ==0) or (count_upper ==0):
return False
return True

c = input("enter youre pass")
if integer(c):
if not checked_str(c):
print("sorry but u should input at least 1 charachter lower case and at least one character uppercase too!")
else:

print("submited!")
else:
print("you forget put at least one integer in youre password! try again")

does any one know whats wrong with this code?

0

24.04.2019

3 ответов

8 просмотров

Lesotho Barcodes

Did you get the indentation right?

0

26.04.2019

Lesotho Barcodes

Where is the self component?

0

26.04.2019

Ceda EI · Accepted Answer

Ceda EI

indentation atleast

0

24.04.2019

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Def integer(x): count = 0 for item in x: if item.isdigit(): count +=1 if count

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