Include 'connection.php'; $sqlall = "SELECT * FROM `staffAttendance` WHERE status= '0'

Question

Include 'connection.php'; $sqlall = "SELECT * FROM `staffAttendance` WHERE status= '0'

";

$resultall = mysqli_query($link, $sqlall);

if(!$resultall){
foreach($resultall as $value){
//echo $value['id'];
$number = $value['id'];
$sid = $value['staff_id'];
$sname = $value['staffname'];
$spos = $value['staffpos'];
$sdep = $value['staffdepart'];
$stime = $value['checking_time'];
}
}else{
echo "";
}

foreach($resultall as $value){
echo "
$value[staff_id]";

}

?>

0

08.11.2018

1 ответов

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The Devs Bot · Accepted Answer

The Devs Bot

It looks like you posted long piece of code, consider editing it out and putting it on hastebin.com and pasting link to it instead. Alternatively, send your code in a file.

0

08.11.2018

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Include 'connection.php'; $sqlall = "SELECT * FROM `staffAttendance` WHERE status= '0'

1 ответов

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