Should I have any concerns about the following code? stdout_handle =

Question

Should I have any concerns about the following code? stdout_handle =

open(stdout_file, "w+")
stderr_handle = open(stderr_file, "w+")

cron_process = subprocess.Popen(cron_command, shell=True, stdout=stdout_handle, stderr=stderr_handle, env={"HTTP_HOST": self.primary_domain})

Is there possibility the buffer could overflow when outputting to a file?

0

12.06.2023

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B4rt · Accepted Answer

B4rt

you need to validate all of your inputs if you want to avoid security problems and you should not use the Shell=True if you really don't need that, this could be really dangerous, if u fail to sanitize the inputs, can allow to execute whatever in the shell. BTW, you should use a With statement for handle files.

0

12.06.2023

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Should I have any concerns about the following code? stdout_handle =

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