Obj& obj::operator=(const obj& other) { data.clear();

Question

Obj& obj::operator=(const obj& other) { data.clear();

for (auto row_it = other.data.begin(); row_it != other.data.end(); ++row_it)
{
// code
}
}

Is this one of the situations where using auto is necessary? I see most websites have used auto. My second question is what's auto deduced to ? Can I write it myself too ?

0

27.02.2024

5 ответов

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Pavel

It is not necessary, but this is one of the cases when auto is approved in most coding standards (even in those that avoid using auto). Basically because the real type can be quite verbose. You can replace it with the real type, which is an iterator type of your container. E.g. if data is std::vector<int> then the type will likely be std::vector<int>::iterator

0

2 месяца назад

Sahand 🏔️ Автор вопроса

Pavel
It is not necessary, but this is one of the cases ...

Thanks. (However the iterator must be const : std::vector<int>::const_iterator)

0

2 месяца назад

Pavel

Sahand 🏔️
Thanks. (However the iterator must be const : std...

Yeah, that's why "likely" :D

0

2 месяца назад