Then what are they talking about here? since that would

Question

C / C++

@^@ ^

Then what are they talking about here? since that would

mean that i, doesn't die even if i_ dies

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16.04.2021

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@^@ ^ Автор вопроса

Ghasem Ramezani
It's exactly about the Dangling Reference as menti...

😂😂😂, I know c++, I was just confused, because according to that statement it means, a reference to a reference should not be eligible if the original dies, which is proper c++, but when I asked you you said, that if i_ dies i should still keep kicking.

0

16.04.2021

Prince Of Persia [field = CE,DM = BLOCK]

@^@ ^
😂😂😂, I know c++, I was just confused, because acco...

😐 a reference is not a type

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16.04.2021

Ghasem Ramezani

@^@ ^
😂😂😂, I know c++, I was just confused, because acco...

References are just like pointers. Reference to a variable is just a reference to it and don't own it. So something like this is wrong: std::string& get_me_something() { std::string some_string = "ghasem is here"; return some_string; } int main() { std::cout << get_me_something() << std::endl; }

0

16.04.2021

@^@ ^ Автор вопроса

Ghasem Ramezani
References are just like pointers. Reference to a ...

☝🏾

0

16.04.2021

Ghasem Ramezani · Accepted Answer

Ghasem Ramezani

It's exactly about the Dangling Reference as mentioned in the first comment. Note that before reading C++ Concurrency in Action you need to learn C++.

0

16.04.2021

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