Base *base = new Derived();

Question

Base *base = new Derived();

//Derived implements interface Base
base->opr(); //Base::opr() is virtual

How is the VTable of Derived accessed, on call to opr(), if the pointer is to Base? Or does the compiler have a means of directly accessing the object the pointer points to?

I know that every object of a class has a pointer to the Vtable for that class(as long as virtual functions are invovled). I just want to know whether the compiler calls an interface not visible to the programmer or something, to get the correct VTable

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14.02.2021

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Ihor · Accepted Answer

Ihor

https://pabloariasal.github.io/2017/06/10/understanding-virtual-tables/

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14.02.2021

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Base *base = new Derived();

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