Hi guys i saw this code in github ```//removed for brevity void executionloop(void){

Question

Hi guys i saw this code in github ```//removed for brevity void executionloop(void){

int ip;
for(;(ip = ((int*)mem)[0]); ((int*)mem)[0]+=4){
int op = ((int*)mem)[ip];
int a = ((int*)mem)[ip+1];
int b = ((int*)mem)[ip+2];
int c = ((int*)mem)[ip+3];
getp(op, a, b, c);
doop(op);
}
}
//removed for brevity```I have 2 question:
1-this loop in which condition will stop?
2-ptr[0]+=4 means ptr[0]=ptr[0]+4 ?
(i mean it adds 4 byte where ptr points to)
sorry for my bad english

0

01.09.2020

5 ответов

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Naweed Автор вопроса

https://hastebin.com/oxobocekum.cpp

0

01.09.2020

Manav | avoid unnecessary messaging me

ip = (((int*)mem)[0]) << this is the condition which will stop the loop. It's a hacky way to do it but (((int*)mem)[0]) value being 0 should stop it

0

01.09.2020

Manav | avoid unnecessary messaging me

No it doesn't mean it adds 4 bytes. It increments the value at ptr[0] by 4

0

01.09.2020

Manav | avoid unnecessary messaging me

Not sure why'd they add 4 to the first element, it looks like a bug, ah they're using it as a pointer to the mem array, whoa. That code can be simplified to a simple for loop with an iterator. Mo need to have the mem array store pointers to iterate over it o.O

0

01.09.2020

Manav | avoid unnecessary messaging me · Accepted Answer

Manav | avoid unnecessary messaging me

Strange it doesn't format to monospace, use hastebin.com or del.dog instead. It's too unappealing to look at it without proper formatting

0

01.09.2020

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Hi guys i saw this code in github ```//removed for brevity void executionloop(void){

5 ответов

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