Yo guys whats wrong w/ this shit template<typename T> struct SP {

Question

Yo guys whats wrong w/ this shit template<typename T> struct SP {

SP() : t{ new T{} } { }

std::enable_if_t<
std::is_class_v<T>, T
>
* operator-> ();

T& operator* () {
return *t;
}

T* t;
};

struct Foo {
int x = 12;
}

SP<Foo> f;
// works fine
auto x = f->x;

//blows up if i do built in type
SP<int> i;
auto z = *i;

when i initialize it with built in types it gives the error no type named type in std::enable_if<false, T>::type
well i think it makes sence due to int is not a class type. but isnt that what enable_is made for? maybe im doin it the wrong way
would this be the right way:

template<typename T,
typename = void>
struct SP {

SP() : t{ new T{} } { }

T& operator* () {
return *t;
}

T* t;
};

template<typename T>
struct SP<T, typename =
enable_if<is_class<T>, T>::type>
{

SP() : t{ new T{} } { }

T* operator-> ();

T& operator* () {
return *t;
}

T* t;
};

struct Foo {
int x = 12;
}

SP<Foo> f;
// works fine
auto x = f->x;

// works fine
SP<int> i;
auto z = *i;

0

30.06.2019

1 ответов

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Manav | avoid unnecessary messaging me · Accepted Answer

Manav | avoid unnecessary messaging me

You might want to read about SFINAE because that is why std::enable_if can do what it does.

0

30.06.2019

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Yo guys whats wrong w/ this shit template<typename T> struct SP {

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