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Array.Prototype.ForEach = function(callback) { for (var i

= 0; i < this.length; i++)
callback(this[i], i, this);
};
why the this keyword is set to the array prototype that we are calling forEach on?

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Because that how JS be

Erfan- Автор вопроса
Thomas
Because that how JS be

When a function is called as a method of an object, its this is set to the object the method is called on.

Erfan- Автор вопроса
Erfan
When a function is called as a method of an object...

when we code something like [1, 2, 3].forEach(el => console.log(el)) It's like forEach is a method on the object on whatever it is called on (if the prototype is a string or number wrapping happens so its object anyway) and the this keyword will be set to object that is what we are calling the forEach method on right?

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