don't know whether this is a silly question to ask.
Somebody, please clear this to me
for example, this is one of the functions in my code
async function ex () {
let i = 1;
while (i >0){
console.log("....No end....");
}
}
Since JS is single-threaded only one task will execute at a time.
How this snippet will execute internally?
I read
All the async tasks are sent to the call back queue.
So is this function also sent to the call back queue? (Since I wrap it in an async) , or it won't.
Q2. NodeJS
I have another doubt also
In node js, I read that all heavy jobs are sent to the libuv instead of v8.
so libuv create a separate thread pool for executing those tasks.
In that case, let's say libuv created four threads and let this function execute in one thread. Since it is an infinite loop that one thread will get blocked.
Then the remaining tasks after that function will execute or not?
1. No, body of the function is synchronous, async before function declaration guarantees that function will return a promise 2. I don't know :3
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