Say I have a typescript interface interface Item { a:

Question

Say I have a typescript interface interface Item { a:

(name: string) => void
b: (value: number) => void
}

Is there a way to get an intersection of the values? E.g.

(name: string) => void | (value: number) => void

I have tried using Item[keyof Item]. But this method is returning me Union type

0

18.09.2020

5 ответов

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Amos Автор вопроса

Alireza Ayinmehr
why not defining them separately? like type typeA ...

Because I will be getting the "Item" from a library. There are ~48 methods in this Item. So I'm seeking for a programmatic way

0

18.09.2020

Alireza Ayinmehr

Amos
Because I will be getting the "Item" from a librar...

so the interface you showed is an example of what libray provides, you need to get the type of Item.a and Item.b to use them with a union, right?

0

18.09.2020

ＭＵＴＨＵ・ＫＵＭＡＲ「メーカー」 🔺

For intersection you want &

0

18.09.2020

Thomas

What you are describing is also the union type

0

18.09.2020

Alireza Ayinmehr · Accepted Answer

Alireza Ayinmehr

why not defining them separately? like type typeA = (name: string) => void type typeB = (value: number) => void interface Item { a: typeA; b: typeB; } and then using typeA | typeB? also you can use Enums, doesn't help much with code complication, but still...

0

18.09.2020

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