Const callAll = (...fns) => (...args) => fns.forEach(fn =>

Question

JavaScript

Const callAll = (...fns) => (...args) => fns.forEach(fn =>

fn && fn(...args))

how this function works ? in the second func are we getting the arguments ?

0

12.10.2019

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Пользователь 61932 · Accepted Answer

Пользователь 61932

callAll is a function that gets a bunch of functions as arguments and returns a function(which has access to all that functions that we have passed it's actually a closure search for it) that gets a bunch of things(args) as argument and then calls all functions with that things

0

12.10.2019

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Const callAll = (...fns) => (...args) => fns.forEach(fn =>

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