Const flatten = arr => arr.reduce( (a, v)

Question

Const flatten = arr => arr.reduce( (a, v)

=> a.concat( Array.isArray(v) ? flatten(v) : v ), []);

const arr = ["♥️", "♣️", "♦️", "♠️"]
.map(symbol => [
"A",
...Array(9).fill(0).map((e, i) => i+2),
..."JQK".split(""),
].map(number => `${number} ${symbol}`))

console.log(flatten(arr))

0

12.12.2017

2 ответов

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Thomas

This is my solution at 97 chars (Using ramda): map(apply(concat),xprod(unnest(['A',map(String,range(2,11)),'J','Q','K']),['♥️','♣️','♦️','♠️']))

0

12.12.2017

Thomas · Accepted Answer

Thomas

Minified this is 253 chars

0

12.12.2017

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Const flatten = arr => arr.reduce( (a, v)

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