It happen when you trying to use "input.nextLine()" after

Question

It happen when you trying to use "input.nextLine()" after

a "input.nextFoo" ?
if so it's a known problem, I solve it by adding one more "input.nextLine()" after the .nextFoo..
the other solution is to use input.nextLine() for all inputs, and convert it later, (example input.nextLine() for int, then ParseInt(string) )

0

13.05.2018

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Albert · Accepted Answer

Albert

Thank's for you ansawer! I discovered the problem, I tried to make with springbootapplication and when they run are not all good working, then I tried to implementes CommandLinne and then goes work perfect!

0

13.05.2018

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It happen when you trying to use "input.nextLine()" after

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