What is the necessity of type-casting the pointer in malloc? Does

A vector, holds a array. It's dynamic, but this dynamic comes into play when the array is filled up, so it expands the array, using malloc/realloc and copies old data to new array. When you do push_back(), if array is not full, it will be o(1) but if it's full it would be o(1)+o(time to reallocate n*existing array size and copy data)

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06.01.2022

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Yamikani ᥀
A vector, holds a array. It's dynamic, but this dy...

thanks for taking out time to type that much I understand now ah

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06.01.2022

Daniele°

No, in C you have autocast from void*. Realloc enlarge Memory allocated, but if can't 1)create new Memory 2)Copy to new address O(n) 3)release old address.

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06.01.2022

Ṃя. Ƒяḁпḱỉè

Peco
yes

No bruh

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06.01.2022

Ghasem Ramezani · Accepted Answer

Ghasem Ramezani

malloc(3) gives you a void* , you must specify the type that you allocated memory for it.

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06.01.2022

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What is the necessity of type-casting the pointer in malloc? Does

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