Guys, a question for the experts. How does a stub for

Question

Guys, a question for the experts. How does a stub for

a method that has not yet been compiled know where to get the IL code for compilation?
I wrote a small test program. Using the GetFunctionPonter() method, I got a function pointer, but since the function has not yet been compiled, it points to a JIT stub, but for all methods, even with a different signature, the stub points to the same address. Clarify please.

Edited: I have not been able to find a solution, I have a guess how it works.
A method stub is invoked with the call instruction, which pushes the address of the next instruction onto the stack, and with this, the JIT determines which method is invoked.

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27.03.2022

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yurii Автор вопроса

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27.03.2022

yurii Автор вопроса

Wizou
Maybe this will help https://blog.birost.com/a?ID=...

Thanks, but this is not what I was looking for. I want to understand how the method stub determines where to get the IL code for further compilation to machine code. (The screenshots show that the method is called during disassembly, I think that this is the JIT stub, but this stub is identical for all other methods, then how does the stub know which method calls it) Edited: I have not been able to find a solution, I have a guess how it works. A method stub is invoked with the call instruction, which pushes the address of the next instruction onto the stack, and with this, the JIT determines which method is invoked.

0

27.03.2022

Wizou

yurii
Thanks, but this is not what I was looking for. I ...

Likely this

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28.03.2022

yurii Автор вопроса

Wizou
Likely this

.

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28.03.2022

Wizou

yurii

those addresses, separated by 8 bytes, doesn't leave much room (only 3 bytes) for extra data between the CALLs though. So maybe just the address itself is the key to another table somewhere else.

0

28.03.2022

yurii Автор вопроса

Wizou
those addresses, separated by 8 bytes, doesn't lea...

maybe

0

28.03.2022

yurii Автор вопроса

Wizou
those addresses, separated by 8 bytes, doesn't lea...