There are 2 pointers head and ptr where ptr =

Question

There are 2 pointers head and ptr where ptr =

head and head points to the linked list 7->0->8->0. I traverse the list using head and it reaches the last node with value 0. When I do head = NULL (that means make the last node disappear) and traverse the list now with help of ptr then ptr is still able to access the nulled last node. Why?

0

30.04.2022

6 ответов

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none Автор вопроса

ohh! So shud I do "delete head" to not allow ptr access the last node but the rest of the list?

0

30.04.2022

Ghasem Ramezani

none
ohh! So shud I do "delete head" to not allow ptr a...

Yes.

0

30.04.2022

none Автор вопроса

Ghasem Ramezani
Yes.

But it's throwing error saying that "heap-use-after-free on address blah". Look ptr = head and ptr stands at the first node while the head has reached the last one and been deleted.

0

30.04.2022

Ghasem Ramezani

none
But it's throwing error saying that "heap-use-afte...

Honestly, I have no way of knowing what you have done. Here is an example simplified without taking into account any best practices: ix.io/3WEb

0

30.04.2022

none Автор вопроса

Ghasem Ramezani
Honestly, I have no way of knowing what you have d...

Okay thankyou

0

30.04.2022

Ghasem Ramezani · Accepted Answer

Ghasem Ramezani

That doesn't mean you make the last node disappear, you just manipulate the location that your pointer pointed to, not the actual memory of that location.

0

30.04.2022

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