Let url = 'https://google.com' useEffect(() => {

Question

JavaScript

Void

Let url = 'https://google.com' useEffect(() => {

console.log(`fetching ${url}...`)
}, [url])

Is something like that ok?

0

08.05.2022

6 ответов

26 просмотров

Ali Souri

the difference is, it re-renders every time the url changes but when given empty brackets, it only renders once before the components are loaded

0

08.05.2022

Ali Souri

You can also use the below model (though there are efficient & better ways using SWR, React Query, etc..) import { useEffect, useState } from "react"; import { getUserDetails } from "../api/services"; export default function useUser() { const [loading, setLoading] = useState<boolean>(true); const [user, setUser] = useState<any>({}); useEffect(() => { setLoading(true); getUserDetails().then(data => { setUser(data.data.data); setLoading(false); }).catch(error => { console.log(error) }); }, []); return { user, loading }; }

0

08.05.2022

Void Автор вопроса

Ali Souri
the difference is, it re-renders every time the ur...

yea and most of the time I don't need it to fech again every redner

0

08.05.2022

Barkuni

Ali Souri
You can also use the below model (though there are...

data.data.data 🤯

0

08.05.2022