Why can i accessed to to the pointed-value *p after

Question

Why can i accessed to to the pointed-value *p after

free the memory ? it is true that the returned value is 0 but I tell myself that I will have either a compilation error or a runtime error.

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19.06.2022

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Issa N'golo Coulibaly Автор вопроса

Manav | avoid unnecessary messaging me
After the delete expression, the pointer becomes i...

but it's a memory safety issue, isn't it? is there a proper way to handle this case and the pointer is invalid right after using the delete expression

0

19.06.2022

Manav | avoid unnecessary messaging me

Issa N'golo Coulibaly
but it's a memory safety issue, isn't it? is there...

It is. There are two ways to go about it, 1. hide it with RAII or 2. set the pointer to null after you delete so subsequent deletes don't do anything plus your pointer is now null so trying to dereference it it will give you errors.

0

19.06.2022

Issa N'golo Coulibaly Автор вопроса

Manav | avoid unnecessary messaging me
It is. There are two ways to go about it, 1. hide ...

thank you very much. i understand the second point. i will googling what's RAII because i don't know what it is. 🙂

0

19.06.2022

Manav | avoid unnecessary messaging me

Issa N'golo Coulibaly
thank you very much. i understand the second point...

👍

0

19.06.2022

Manav | avoid unnecessary messaging me · Accepted Answer

Manav | avoid unnecessary messaging me

After the delete expression, the pointer becomes invalid. According to the C++ standard access of such a pointer is implementation defined (a type of undefined behaviour). Some platforms may give you segfault, some might not. It is not true. Delete doesn't set the pointer to null.

0

19.06.2022

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Why can i accessed to to the pointed-value *p after

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