Pls change the $result to $stmt (the variable name

Question

Pls change the $result to $stmt (the variable name

you defined for the output)

and can you give me the output of
print_r($stmt);exit();
? (put it right before the switch)

0

09.05.2019

3 ответов

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Пользователь 627f3

var_dump($stmt) object(mysqli_stmt)#2 (10) { ["affected_rows"]=> int(1) ["insert_id"]=> int(0) ["num_rows"]=> int(1) ["param_count"]=> int(1) ["field_count"]=> int(3) ["errno"]=> int(0) ["error"]=> string(0) "" ["error_list"]=> array(0) { } ["sqlstate"]=> string(5) "00000" ["id"]=> int(2) }

0

09.05.2019

Пользователь 627f3

var_dump($result) NULL

0

09.05.2019

Пользователь 627f3 · Accepted Answer

Пользователь 627f3

mysqli_stmt Object ( [affected_rows] => 1 [insert_id] => 0 [num_rows] => 1 [param_count] => 1 [field_count] => 3 [errno] => 0 [error] => [error_list] => Array ( ) [sqlstate] => 00000 [id] => 1 )

0

09.05.2019

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Pls change the $result to $stmt (the variable name

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