I open my txt file that is next to my

Question

I open my txt file that is next to my

program . And open with cmd like this :
MyProgramPath txtPath
But i see the index error .
Which one is correct for me ? args[0] or args[1] ?

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21.07.2019

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Пользователь 616e3

args[0]

0

21.07.2019

Пользователь 616e3 · Accepted Answer

if you open .txt through the "open as" function and select your application, it will give the full path to the file and then the expression will be true StreamReader sr = new StreamReader (args [0]); If you try to transfer the file name via cmd, it will not be able to open it for the reason that the application was invoked by means of cmd. Simply put args [0] will contain the name of the desired file, but when you try to open it the application will call the CurrentDirectory function to get the current directory of the application, but this directory will be C: \ Users \ Admin

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I open my txt file that is next to my

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