Today: Const a = x?.a; const b = x?.b; Tomorrow?.: const { a, b

This is a strange syntax though, not even kotlin has anything like this. also the dot at the end could be misinterpreted as part of the destructuring remember js doesn't enforce semi colons and can be put on one line

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6 месяцев назад

ＭＵＴＨＵ・ＫＵＭＡＲ「メーカー」 🔺 Автор вопроса

Richard | Dm for Paid Support
This is a strange syntax though, not even kotlin h...

You can write this today and have a syntax error: x.

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6 месяцев назад

ＭＵＴＨＵ・ＫＵＭＡＲ「メーカー」 🔺 Автор вопроса

The JS parser would know we're in a destructuring context, and expect the expression to end with an identifier or optional access

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6 месяцев назад

Richard | Dm for Paid Support

ＭＵＴＨＵ・ＫＵＭＡＲ「メーカー」 🔺
The JS parser would know we're in a destructuring ...

what if you want to destructure an optionally chained object

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6 месяцев назад

Richard | Dm for Paid Support · Accepted Answer

Richard | Dm for Paid Support

Isn't this already implemented as Nullish coalescing operator (??)

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6 месяцев назад

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Today: Const a = x?.a; const b = x?.b; Tomorrow?.: const { a, b

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