Public byte[] readVideo(String filePath, int start, int end) throws IOException

Question

Public byte[] readVideo(String filePath, int start, int end) throws IOException

{
Path path = Paths.get(filePath);
try (RandomAccessFile file = new RandomAccessFile(path.toFile(), "r")) {
int bufferSize = 5 * 1024 * 1024; // 10 mb
byte[] buffer = new byte[bufferSize];
ByteArrayOutputStream outputStream = new ByteArrayOutputStream();
int bytesRead;
int totalBytes = start;
while ((bytesRead = file.read(buffer)) != -1 && totalBytes < end) {
outputStream.write(buffer, 0, bytesRead);
totalBytes += bytesRead;
}
outputStream.flush();
logger.info("output stream::: " + outputStream.toByteArray());
return outputStream.toByteArray();
}
}

Do you mean like this?

0

05.04.2024

1 ответов

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Thomas · Accepted Answer

Thomas

You can't just set totalBytes equal to start

0

8 месяцев назад

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Public byte[] readVideo(String filePath, int start, int end) throws IOException

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