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If we do not use constexpr , will the same

program do calculation at compile time or at run time ? see this example https://pastebin.com/yAh9eyDN

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Well for that simple code, if you don't disable optimization, the value stored in x would be 200. Assuming you don't do optimization, and you add constexpr specifier to the function, yes the calculation will be done at compile time. x would be 200

Peace
what kind of optimization ?

compilers usually do optimization by default, you can enable, disable these using compiler flags

Peace
what kind of optimization ?

What compiler do you normally use? msvc? gcc, clang?

Peace
gcc

https://gcc.gnu.org/onlinedocs/gcc/Optimize-Options.html

Peace
what kind of optimization ?

ah i forgot to mention, constexpr doesn't gurantee that the expression will be evaluated during compile time :D

constexpr guaranties compile time calculation. Non-constexpr may or may not be optimized away, unless you disable optimization, and then it will, well, not optimized

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