Function sum(arr, n) { if (n <= 0) {

Question

Function sum(arr, n) { if (n <= 0) {

return 0;
} else {
return sum(arr, n-1) + arr[n-1];
}
}
sum([2, 3, 4, 5], 3)

Output: 9 How?

In iteration 1:
if is not satisfied so it goes to else part, now here
sum(arr, n-1) becomes sum([2,3,4,5], 2), where does this go to in next iteration?
arr[n-1] becomes arr[2] which is 4

0

24.04.2020

2 ответов

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commandline Автор вопроса

its sum is 9 when sum([2,3,4,5],2) is passed!

0

24.04.2020

Edwing123 · Accepted Answer

Edwing123

It's summing 4, 3 and 2

0

24.04.2020

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