Is it possible to inform TS not to expand firstname

Question

Is it possible to inform TS not to expand firstname

and lastname when building the template literals of same object?

export interface Person {
first_name: string,
last_name: string,
name: `${Person['first_name']} ${Person['last_name']}`
}
as above name prop type will be string.

or that is only possible by constructing the type from a literal expression (with const assertion)?

0

08.06.2022

3 ответов

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function person <F extends string, L extends string>(first: F, last: L, name: `${F} ${L}`) { return { first, last, name }; } person( "Muthu", "Kumar", "" // Argument of type '""' is not assignable to parameter of type '"Muthu Kumar"'.(2345) )

0

08.06.2022

Thomas

ＭＵＴＨＵ・ＫＵＭＡＲ「メーカー」 🔺
function person <F extends string, L extends strin...

Might as well just concat in there at this point

0

08.06.2022

Thomas · Accepted Answer

Thomas

export interface Person<FirstName extends string, LastName extends string> {

0

08.06.2022

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Is it possible to inform TS not to expand firstname

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