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Hey there. Does arithmetic operations on iterators work in O(n) ? Example: std::vector<int>::iterator

it = v.begin();
it += 6;

Is "it += 6;" done in O(n) or constant time ?

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Sahand-🏔️ Автор вопроса

Can anyone help out?

Sahand 🏔️
Can anyone help out?

i think its constant, just move address

Sahand-🏔️ Автор вопроса
²
i think its constant, just move address

So it's constant for std vector but for std list (that no random access is available) it'll be O(n) I think. Because the compiler says no operator '+=' is overloaded.

Sahand-🏔️ Автор вопроса
²
screenshot oh, you right

Which book is it

²
screenshot oh, you right

Would be interesting to know if they give you any guarantees on complexity, but likely they won't

Sahand-🏔️ Автор вопроса
BinaryByter
Would be interesting to know if they give you any ...

guarantees on the complexity of arithmetic operations on iterators?

BinaryByter
Would be interesting to know if they give you any ...

You can see here that the operation on a random access I iterators is not O(1) while others iterators are O(n) https://en.cppreference.com/w/cpp/iterator/distance

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