Vector<String>Ss; For(Int i=0;i<n;i++) { cin.ignore();

Question

C / C++

Hima

Vector<String>Ss; For(Int i=0;i<n;i++) { cin.ignore();

string s;
getline(cin,s);
ss.push_back(s);
}
not working for input:
n=2
4
5

why 5 is not being pushed to the vector?

0

12.03.2022

5 ответов

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Hima Автор вопроса

didnt work

0

12.03.2022

Pavel

Hima
didnt work

I don't know how the code before the loop looks like, but this example works for me: #include <iostream> #include <vector> #include <string> using namespace std; int main() { int n = 2; vector<string>ss; for(int i=0;i<n;i++) { string s; getline(cin, s); ss.push_back(s); } cout << "\n"; for (string value : ss) { cout << value << "\n"; } }

0

12.03.2022

Hima Автор вопроса

Pavel
I don't know how the code before the loop looks li...

works fine, but what if you do int n; cin>>n; instead hardcoding

0

13.03.2022

Pavel

Hima
works fine, but what if you do int n; cin>>n...

#include <iostream> #include <vector> #include <string> using namespace std; int main() { int n; cin>>n; cin.ignore(); vector<string>ss; for(int i=0;i<n;i++) { string s; getline(cin, s); ss.push_back(s); } cout << "\n"; for (string value : ss) { cout << value << "\n"; } }

0

13.03.2022

Pavel · Accepted Answer

Pavel

i would guess cin.ignore drops the value, you probably need to do it once before the loop (or right after the operation that requires it)

0

12.03.2022

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Vector<String>Ss; For(Int i=0;i<n;i++) { cin.ignore();

5 ответов

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