Something like let lengthMatch = parentArr[0].length; parentArr.forEach( arr => { arr.length

Question

JavaScript

david

Something like let lengthMatch = parentArr[0].length; parentArr.forEach( arr => { arr.length

=== lengthMatch ? console.log( "it's a match" ) : console.log( "different lengths :(" );

})

0

03.11.2020

8 ответов

17 просмотров

J : Vaccinated 🇨🇦

parentArr.every((c, i, p) => p[0].length === c.length)

0

03.11.2020

Edwing123

J : Vaccinated 🇨🇦
parentArr.every((c, i, p) => p[0].length === c.len...

Is this checking if all childs'length is pointing to the same value ?

0

03.11.2020

J : Vaccinated 🇨🇦

Edwing123
Is this checking if all childs'length is pointing ...

Yes

0

03.11.2020

Banana

J : Vaccinated 🇨🇦
parentArr.every((c, i, p) => p[0].length === c.len...

You can use array destructuring for the third parameter.

0

04.11.2020

Edwing123

Banana
You can use array destructuring for the third para...

{ length: l }

0

04.11.2020

Banana

Edwing123
{ length: l }

(c,i,[{length:n}])

0

04.11.2020

J : Vaccinated 🇨🇦

J : Vaccinated 🇨🇦
parentArr.every((c, i, p) => p[0].length === c.len...

^

0

04.11.2020

Akash Rana · Accepted Answer

Akash Rana

This can be work ,I think🧐

0

03.11.2020

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Something like let lengthMatch = parentArr[0].length; parentArr.forEach( arr => { arr.length

8 ответов

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